Linear Inequalities - Exercise 3

Find the critical numbers of the inequality given below by solving |2x - 3| = 1. Then test intervals and find the solution interval or intervals. The Justification has been given - No further justification is needed.

STATEMENT

JUSTIFICATION

|2x - 3| ≥ 1
|2x - 3| = 1 is related equation

Given

Use the Division and Addition Properties of Equality to solve each case of the absolute value equation and find critical numbers.

Use the property: Critical Numbers Define Solution Interval Endpoints to test and determine solutions.